32=(1/4)^x+1

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Solution for 32=(1/4)^x+1 equation: 



32=(1/4)^x+1

We move all terms to the left:

32-((1/4)^x+1)=0



Domain of the equation: 4)^x+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/4)^x+1)+32=0

We multiply all the terms by the denominator


-((+1+32*4)^x+1)=0



We calculate terms in parentheses: -((+1+32*4)^x+1), so:

(+1+32*4)^x+1

We add all the numbers together, and all the variables

129^x+1

Back to the equation:

-(129^x+1)



We get rid of parentheses

-129^x-1=0

We move all terms containing x to the left, all other terms to the right

-129^x=1

x=1/1

x=1

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